Graficar la funcion seno en 3d con Python y Matplotlib

import numpy as np

import matplotlib.pyplot as plt

from mpl_toolkits import mplot3d

x = np.linspace(-6,6,30)

y = np.linspace(-6,6,30)

X,Y = np.meshgrid(x,y)

Z = np.sin(X)

fig = plt.figure()

ax = plt.axes(projection='3d')

ax.contour3D(X,Y,Z,50,cmap='binary')

plt.show()